Evaluatedisplaystylearctanleft(-frac1sqrt3 ight) Explanation:Trig table gives:displaystyle anx=left(-frac1sqrt3 ight)=frac-sqrt33 ...

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displaystylearctanleft(frac1sqrt3 ight)=fracpi6quad extorquad30^o Explanation:This ratio is just one of the traditional trigonometric triangles: displaystylearctan ...
displaystyleleft( heta=npi-left(fracpi6 ight)left(aaa ight)ninmathbbZ ight. Explanation:Letdisplaystyle heta=arctanleft(-fracsqrt33 ight)= an^-1left(-fracsqrt33 ight) ...
displaystylearctanleft(fracsqrt33 ight)=fracpi6=30^circ Explanation:Note thatdisplaystylefracsqrt33=frac1sqrt3 here is a ...
https://math.stackexchange.com/questions/850056/what-am-i-supposed-to-do-here-now-tan-pi-8-sqrt2-1-complex-analysis
If girlfriend let sqrt1+i=x+iy, climate (x^2-y^2)+i2xy=1+i. Then x^2-y^2=1 and 2xy=1. Hence (x^2+y^2)^2=(x^2-y^2)^2+4x^2y^2=2. Hence x^2+y^2=sqrt2. Now adding this two terms x^2=frac1+sqrt22 ...

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arctan 2 is not a rational multiple that pi. If that were, then for part integer n > 0, us would have actually (1 + 2i)^n is real. Top top the various other hand, if we specify a_n := operatornameIm((1 + 2i)^n) ...
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left< eginarray together l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l together 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>

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